Simple Calculator In C Programming | Coding Challange Day 1

Simple Calculator is a C language-based application used for performing all the simple arithmetic operations like addition, multiplication, division, and subtraction. The application can be made using basic knowledge of C like if-else statements, loops, etc. The functionalities of the application are men

Addition

Subtraction

Multiplication

Division

Logarithmic values

Square roots

Program:

#include <stdio.h>

#include <math.h>

int main() {

    int choice;

    double num1, num2, result;

    printf("Simple Calculator\n");

    printf("1. Addition\n");

    printf("2. Subtraction\n");

    printf("3. Multiplication\n");

    printf("4. Division\n");

    printf("5. Logarithmic values\n");

    printf("6. Square root\n");

    printf("Enter your choice: ");

    scanf("%d", &choice);

    switch(choice) {

        case 1:

            printf("Enter two numbers: ");

            scanf("%lf %lf", &num1, &num2);

            result = num1 + num2;

            printf("Result: %.2lf\n", result);

            break;

        case 2:

            printf("Enter two numbers: ");

            scanf("%lf %lf", &num1, &num2);

            result = num1 - num2;

            printf("Result: %.2lf\n", result);

            break;

        case 3:

            printf("Enter two numbers: ");

            scanf("%lf %lf", &num1, &num2);

            result = num1 * num2;

            printf("Result: %.2lf\n", result);

            break;

        case 4:

            printf("Enter two numbers: ");

            scanf("%lf %lf", &num1, &num2);

            if(num2 == 0) {

                printf("Error! Division by zero.\n");

            } else {

                result = num1 / num2;

                printf("Result: %.2lf\n", result);

            }

            break;

        case 5:

            printf("Enter a number: ");

            scanf("%lf", &num1);

            result = log(num1);

            printf("Result: %.2lf\n", result);

            break;

        case 6:

            printf("Enter a number: ");

            scanf("%lf", &num1);

            if(num1 < 0) {

                printf("Error! Square root of a negative number.\n");

            } else {

                result = sqrt(num1);

                printf("Result: %.2lf\n", result);

            }

            break;

        default:

            printf("Invalid choice\n");

    }

    return 0;

}